y^3+4y^2=21y

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Solution for y^3+4y^2=21y equation:


Simplifying
y3 + 4y2 = 21y

Reorder the terms:
4y2 + y3 = 21y

Solving
4y2 + y3 = 21y

Solving for variable 'y'.

Reorder the terms:
-21y + 4y2 + y3 = 21y + -21y

Combine like terms: 21y + -21y = 0
-21y + 4y2 + y3 = 0

Factor out the Greatest Common Factor (GCF), 'y'.
y(-21 + 4y + y2) = 0

Factor a trinomial.
y((-7 + -1y)(3 + -1y)) = 0

Subproblem 1

Set the factor 'y' equal to zero and attempt to solve: Simplifying y = 0 Solving y = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y = 0

Subproblem 2

Set the factor '(-7 + -1y)' equal to zero and attempt to solve: Simplifying -7 + -1y = 0 Solving -7 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1y = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1y = 0 + 7 -1y = 0 + 7 Combine like terms: 0 + 7 = 7 -1y = 7 Divide each side by '-1'. y = -7 Simplifying y = -7

Subproblem 3

Set the factor '(3 + -1y)' equal to zero and attempt to solve: Simplifying 3 + -1y = 0 Solving 3 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1y = 0 + -3 -1y = 0 + -3 Combine like terms: 0 + -3 = -3 -1y = -3 Divide each side by '-1'. y = 3 Simplifying y = 3

Solution

y = {0, -7, 3}

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